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en:eingabe_der_maschinenparameter_und_konfiguration:schneckenelemente:exzentrische_knetbloecke [2025/08/17 01:24] deppe2en:eingabe_der_maschinenparameter_und_konfiguration:schneckenelemente:exzentrische_knetbloecke [2025/11/02 21:46] (aktuell) deppe2
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 If the comb angle is zero, the diameter ratio of the three-course profile is at the maximum point. If the comb angle is zero, the diameter ratio of the three-course profile is at the maximum point.
  
-Maximum diameter ratio of three-way profile (i=3) +** Maximum diameter ratio of three-way profile (i=3)** 
-$$D_{v,3} = D_{a,3 \max} = \frac{1}{2 \cdot \cos\left(\frac{\pi}{2 \cdot i}\right) - 1} = 1.366$$+$$D_{v,3} = D_{a,3 \max} = \frac{1}{2 \cdot \cos\left(\frac{\pi}{2 \cdot i}\right) - 1} = 1.366 \tag{Equation 3-13}$$
  
-Equation 3-13 
  
-Outer diameter of three-course profile+**Outer diameter of three-course profile**
  
-$$D_{a,3} = \frac{2 \cdot a}{1 + \frac{1}{D_{v,3}}}$$+$$D_{a,3} = \frac{2 \cdot a}{1 + \frac{1}{D_{v,3}}} \tag{Equation 3-14}$$
  
-Equation 3-14 
  
-Eccentricity e+**Eccentricity $e$**
  
-$$e = \frac{D_{a,2} - D_{a,3}}{2}$$+$$e = \frac{D_{a,2} - D_{a,3}}{2} \tag{Equation 3-15}$$
  
-Equation 3-15 
  
-Inside diameter of three-course profile+**Inside diameter of three-course profile**
  
-$$D_{i,3} = 2 \cdot a - D_{a,3}$$+$$D_{i,3} = 2 \cdot a - D_{a,3} \tag{Equation 3-16}$$
  
  
-Equation 3-16 
  
 The graph below shows the standard profile and the eccentric profile. The black profile is centered and symmetrical over the rotation center O point. It is also symmetrical over 3 axes: AD, BE and CF. On the other hand, the red profile is symmetrical only over x-axis. The graph below shows the standard profile and the eccentric profile. The black profile is centered and symmetrical over the rotation center O point. It is also symmetrical over 3 axes: AD, BE and CF. On the other hand, the red profile is symmetrical only over x-axis.
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 This profile shows that the comb angles are zero. Therefore the flank angles of the standard profile are the same: This profile shows that the comb angles are zero. Therefore the flank angles of the standard profile are the same:
-$$\phi_{k,3} = \phi_{g,3} = 0$$ +$$\phi_{k,3} = \phi_{g,3} = 0 \tag{Equation 3-17}$$
-Comb angle: Equation 3-17+
  
-$$\angle AOB = \angle BOC = \angle COD = \Omega_3 = 60°$$ +**Comb angle:**
-Flank angle: Equation 3-18+
  
-$$R_{a,3} = \frac{D_{a,3}}{2}$$ +$$\angle AOB = \angle BOC = \angle COD = \Omega_3 = 60° \tag{Equation 3-18}$$ 
-Outside radiusEquation 3-19+**Flank angle:**
  
-$$R_{i,3} = \frac{D_{i,3}}{2} = \left(a - \frac{D_{a,3}}{2}\right)$$ +$$R_{a,3} = \frac{D_{a,3}}{2} \tag{Equation 3-19}$$ 
-Inside radius: Equation 3-20+**Outside radius:** 
 + 
 +$$R_{i,3} = \frac{D_{i,3}}{2} = \left(a - \frac{D_{a,3}}{2}\right) \tag{Equation 3-20}$$ 
 +**Inside radius:** 
  
 The coordinates of the points in the three-course standard profile can be calculated by these geometry sizes. Because the profile is symmetrical, only half the contour is selected as the calculation object. The coordinates of the points in the three-course standard profile can be calculated by these geometry sizes. Because the profile is symmetrical, only half the contour is selected as the calculation object.