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en:grundlagenhandbuch:strangabkuehlung [2026/05/28 10:05] – [Calculation of the output] deppe2en:grundlagenhandbuch:strangabkuehlung [2026/08/17 11:01] (aktuell) – [Determination of the temperature field] paal
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 After a few simplifications, the following expression results: After a few simplifications, the following expression results:
  
-$$T_{i+1,j} = T_{i,j} + \frac{\Delta t \cdot a}{R^2} \left[(T_{i,j+1} - 2T_{i,j} + T_{i,j-1}) \cdot N^2 + \frac{N}{j} \cdot \frac{T_{i,j+1} - T_{i,j-1}}{2}\right] \tag{13}$$+$$T_{i+1,j} = T_{i,j} + \frac{\Delta t \cdot a}{R^2} \left[(T_{i,j+1} - 2T_{i,j} + T_{i,j-1}) \cdot N^2 + \frac{N^2}{j} \cdot \frac{T_{i,j+1} - T_{i,j-1}}{2}\right] \tag{13}$$ 
  
 In addition, the time difference Δt can be described by the ratio of the length to the pull-off speed: In addition, the time difference Δt can be described by the ratio of the length to the pull-off speed:
  
-$$T_{i+1,j} = T_{i,j} + \frac{\Delta x \cdot a}{v_{ab} \cdot R^2} \left[(T_{i,j+1} - 2T_{i,j} + T_{i,j-1}) \cdot N^2 + \frac{N^2 T_{i,j+1} - T_{i,j-1}}{j \cdot 2}\right] \tag{14}$$+$$T_{i+1,j} = T_{i,j} + \frac{\Delta x \cdot a}{v_{ab} \cdot R^2} \left[(T_{i,j+1} - 2T_{i,j} + T_{i,j-1}) \cdot N^2 + \frac{N^2}{j} \cdot \frac{T_{i,j+1} - T_{i,j-1}}{2}\right] \tag{14}$$
  
 $$T_{i+1,j} = T_{i,j} + \frac{\Delta x \cdot a \cdot N^2}{v_{ab} \cdot R^2} \left[(T_{i,j+1} - 2T_{i,j} + T_{i,j-1}) + \frac{1}{j} \frac{T_{i,j+1} - T_{i,j-1}}{2}\right] \tag{14.1}$$ $$T_{i+1,j} = T_{i,j} + \frac{\Delta x \cdot a \cdot N^2}{v_{ab} \cdot R^2} \left[(T_{i,j+1} - 2T_{i,j} + T_{i,j-1}) + \frac{1}{j} \frac{T_{i,j+1} - T_{i,j-1}}{2}\right] \tag{14.1}$$